Dear All
The z is the complex variable and the function f(z) is defined as (exp(z^2)1)/(z^2) if z not equal zero and defined as 1 if z=0 . It is asked for its differentiation up to 2k steps evaluated at z=0 i.e. f(2k)(0) . The answers are as :
1) 2k(2k1) .... (k+2)
2) (2k)!/(k)!
3) 1
4) not computable , since not analytic at z=0
Which one is correct in your opinion ?
complex function ?

 Posts: 157
 Joined: Sun Oct 14, 2012 12:15 pm
Re: complex function ?
its not analytic at 0 since the cauchyriemann equations are not satisfied (unless i made a calculation error )

 Posts: 7
 Joined: Tue Mar 05, 2013 10:22 am
Re: complex function ?
I think you've made a mistake math applicant. The pole of e^(z^2)1 at z=0 is order 2. Notice that the first derivative is 2ze^(z^2) which has a zero at z=0 and taking another derivative we find that the second derivative is not zero, so the zero is second order. Ergo e^(z^2)1/z^2 is entire. Anyway I'd suggest taking the Taylor series for e^(z^2)1 and then dividing by z^2 to get the correct Taylor series which should give you all the derivatives you could possibly need.