∫_(-∞)^∞▒〖Ae^(〖-λ(x-a)〗^2 ) dx=1〗

Solve for A .

## Please Help

### Re: Please Help

Do you mean $$\int_{-\infty}^\infty Ae^{-\lambda (x-a)^2} dx = 1$$ or $$\int_{-\infty}^\infty Ae^{\left[-\lambda (x-a)\right]^2} dx = 1$$?fawazshitu wrote:∫_(-∞)^∞▒〖Ae^(〖-λ(x-a)〗^2 ) dx=1〗

Solve for A .