Yet another question from 0568 -
h(x) = integral from 0 to x^2 of e^(x+t) dt
h'(1) = ?
Can someone point out where I went wrong, please?
h'(x) = e^(x+x^2)*(2x) - e^(x+0)
h'(1) = 2e^2 - e
but the correct answer is 3e^2 - e.
thanks.
0568 #24
Yet another question from 0568 -
h(x) = integral from 0 to x^2 of e^(x+t) dt
h'(1) = ?
Can someone point out where I went wrong, please?
h'(x) = e^(x+x^2)*(2x) - e^(x+0)
h'(1) = 2e^2 - e
but the correct answer is 3e^2 - e.
thanks.
this is just special case of Leibniz Integral rule
http://mathworld.wolfram.com/LeibnizIntegralRule.html