Can some explaine the Q27 from GRE9367?
I select B, but the correct answer is A.
I do not know why f(y) should be f(y)^2.
sorry, I can not write the Q here, because I do not have Latex:(
Thanks
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about Q 37 also I have problem,
I chose A as answer, because the first row product in 3 , then det =9*3=27 and after that the third row product in -4, then det=27*(-4)=-108,
but answer is -27. I do not know why:( can someone explain that?
Thanks
GRE9367#27and 37
Re: GRE9367#27and 37
#27
x^2 + z^2 = r^2 in the plane y = y_0, and f(y_0) is the radius.
#37
You are exchanging rows 2 and 3, which gives you a negative 27
Now, to the new row 2 you are adding the new row 3 times a constant. This doesn't change the determinant. If you dont see why, calculate this
|a b|
|c d|
And the same while adding to any line the other one times any number you choose
x^2 + z^2 = r^2 in the plane y = y_0, and f(y_0) is the radius.
#37
You are exchanging rows 2 and 3, which gives you a negative 27
Now, to the new row 2 you are adding the new row 3 times a constant. This doesn't change the determinant. If you dont see why, calculate this
|a b|
|c d|
And the same while adding to any line the other one times any number you choose