Need a little help please!!!!

Maximize the function f(x,y) =sqrt(x^2+y^2) subject to the constraints x+3y≤10,x≥0 and y≥0.

## Maximization

### Re: Maximization

Look up the lagrangian multiplier method.

### Re: Maximization

You can just notice that the maximum is achieved when x+3y=10. Then just substitute x=10-3y in x^2+y^2 and maximize it in the interval y \in [0, 10/3]. Take a square root of the result and that's it.

### Re: Maximization

First sketch the domain. It is a triangle in quarant I. Then you substitude the vertices into the given function. No need to try (0, 0) 'cause the function is bigger when x and y are getting bigger.

### Re: Maximization

Spice girl, do you get f(10, 0) = 10 as an answer?

### Re: Maximization

The function is simply the distance from the origin. Our domain is a triangle in the first quadrant, with the furthest vertex at (10,0). Thus, the answer is 10.