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GR9768 Q 64 Option 3? slope bounded?

Posted: Tue Oct 11, 2011 7:00 am
by Hom
Here is a old post regarding this questions below
(http://www.mathematicsgre.com/viewtopic ... 8+64#p1799)

Ques: Suppose that f is a continuous real-valued function defined on the closed interval [0,1]. Which of the following must be true ?
III. There is a constant E > 0 such that |f(x) -f(y)| <= E |x-y| for all x and y in [0,1]

The answer rejected III. The discussion said that not all the function are uniformly continuous.

But if we rewrite the condition as:
|f(x) -f(y)| / |x-y| = |K| <= E

So the left hand side become the abs of the slope. I am wondering for a continuous function defined on a closed interval, is it possible that the slope in not bounded?

Re: GR9768 Q 64 Option 3? slope bounded?

Posted: Tue Oct 11, 2011 1:11 pm
by blitzer6266
Any non-Lipschitz function does the job

consider the square root of x...

Re: GR9768 Q 64 Option 3? slope bounded?

Posted: Tue Oct 11, 2011 9:10 pm
by Hom
blitzer6266 wrote:Any non-Lipschitz function does the job

consider the square root of x...
That's a brilliant example. Thank you :D