Hi,guys, I am doing the practice tests and have several problems in it. They are: GR9768#19, I cannot figure out the second table;GR9768#48, this one is really tough, I just can eliminate B,C and E,but cannot select from A and D; GR9768#57, hope someone can explain for me this; GR9768#59, really confused;
Thank you all guys!!!
Some questions about Subject in GR9768
Re: Some questions about Subject in GR9768
#19
3rd column has two a's.
#57
Just check the ring axioms. 2 isn't closed under addition. You can get a polynomial whose degree is odd
3rd column has two a's.
#57
Just check the ring axioms. 2 isn't closed under addition. You can get a polynomial whose degree is odd
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Re: Some questions about Subject in GR9768
Thank you, I can figure out as you said, what about #48;? I still cannot work it outNapot wrote:#19
3rd column has two a's.
#57
Just check the ring axioms. 2 isn't closed under addition. You can get a polynomial whose degree is odd
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Re: Some questions about Subject in GR9768
For 59: http://www.mathematicsgre.com/viewtopic ... 3156#p3156
for 48, rewrite v as v= u - x^(1/3) + 1
As x ranges from 0 to 1, this gives a family of lines with slope 1
Because v=1+y ranges from 1 to 2 as y ranges from 0 to 1, the image looks like A
for 48, rewrite v as v= u - x^(1/3) + 1
As x ranges from 0 to 1, this gives a family of lines with slope 1
Because v=1+y ranges from 1 to 2 as y ranges from 0 to 1, the image looks like A
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Re: Some questions about Subject in GR9768
Thank you so much!blitzer6266 wrote:For 59: http://www.mathematicsgre.com/viewtopic ... 3156#p3156
for 48, rewrite v as v= u - x^(1/3) + 1
As x ranges from 0 to 1, this gives a family of lines with slope 1
Because v=1+y ranges from 1 to 2 as y ranges from 0 to 1, the image looks like A