Is X^2+X+1 a factor of X^3+X+1 in Z/3Z?
I was thinking since X=1 make X^2+X+1=0 and also X^3+X+1, can we say that there exists a P(X) that X^3+X+1 = (X^2+X+1) p(X)
Thanks
Factors question
Re: Factors question
No it is not, try long division.
Re: Factors question
I tried to use this method,PNT wrote:No it is not, try long division.
Assuming (x^2+x+1)(ax+b) = ax^3+(a+b)x^2+(a+b)x+(b+1) = X^3+X+1,
then by checking X^3 and the constant, we got a=3n+1 , b = 3m (n,m are of Z). then (a+b)X^2 --> X^2 !=0 which contradicts the assumption.
is this logic ok or any better solution to check?
Thanks,
Re: Factors question
well since x^2+x+1 and x^3+x+1 both have 1 as the leading coeff and the zero power coeff you know ax+b has to have the form x+1, which doesnt work.
Re: Factors question
Well, I think Hom just misunderstood the question and led us to another direction....
I have his materials, and i think the question is:
What are the common divisors of x^2+x+1 and x^3+x+1 in Z/3Z
I have his materials, and i think the question is:
What are the common divisors of x^2+x+1 and x^3+x+1 in Z/3Z
Re: Factors question
in that case use the euclidean algorithm and you get x+2
Re: Factors question
and 1....PNT wrote:in that case use the euclidean algorithm and you get x+2
Re: Factors question
Thank you guys. Appreciate it.mhyyh wrote:and 1....PNT wrote:in that case use the euclidean algorithm and you get x+2