Consider the system of equations
ax^2 + by^3 = c
dx^2 + ey^3 = f
where a, b, c, d, e, and f are real constants and ae != bd. The maximum number of real solutions (x,y) of the system is:
The answer is two. Though I'm not sure how they got that. If you subtract one from the other you get (a-d)x^2 + (b-e)y^3 = c-f, which has at least 3 solutions, 2 for positive and negatives values of x when y is 0, and 1 for y when x is 0. What am I missing?
GRE test 9367 #45
Re: GRE test 9367 #45
Careful. Not every solution to "(a-d)x^2 + (b-e)y^3 = c-f" also solves both equations individually.
Let's do a substitutions of variables. Let s = x^2, t = y^3. Now you get a system of linear equations in s and t:
a s + b t = c
d s + e t = f
Since the coefficient matrix is non-singular, the system has precisely one solution (s,t). Now let's undo the change of variables. There are at most two real solutions to x^2 = s, and precisely one (not counting multiplicities) for y^3 = t.
That's at most two real solutions.
Let's do a substitutions of variables. Let s = x^2, t = y^3. Now you get a system of linear equations in s and t:
a s + b t = c
d s + e t = f
Since the coefficient matrix is non-singular, the system has precisely one solution (s,t). Now let's undo the change of variables. There are at most two real solutions to x^2 = s, and precisely one (not counting multiplicities) for y^3 = t.
That's at most two real solutions.
Re: GRE test 9367 #45
Damn. That is an awesome explanation. High five and thanks for the response. wish us luck tomorrow ~_~